Strings and flow control statments in python

[dopeobama]

strings :
Its strings can use either single or double quotation marks, and you can have quotation marks of one kind inside a string that uses the other kind (i.e. “He said ’hello’.” is valid). Multiline strings are enclosed in _triple double (or single) quotes_ (“”“). Python strings are always Unicode, but there is another string type that is pure bytes. Those are called bytestrings and are represented with the b prefix, for example b'Hello \xce\xb1'. . To fill a string with values, you use the % (modulo) operator and a tuple. Each %s gets replaced with an item from the tuple, left to right, and you can also use dictionary substitutions, like so:

>>> print("Name: %s\
Number: %s\
String: %s" % (myclass.name, 3, 3 * "-"))
Name: Stavros
Number: 3
String: ---

strString = """This is
a multiline
string."""

# WARNING: Watch out for the trailing s in "%(key)s".
>>> print("This %(verb)s a %(noun)s." % {"noun": "test", "verb": "is"})
This is a test.

>>> name = "Stavros"
>>> "Hello, {}!".format(name)
Hello, Stavros!
>>> print(f"Hello, {name}!")
Hello, Stavros!

Flow control statements:

Flow control statements are if, for, and while. There is no switch; instead, use if. Use for to enumerate through members of a list. To obtain a sequence of numbers you can iterate over, use range(<number>). These statements’ syntax is thus:

>>> print(range(10))
range(0, 10)
>>> rangelist = list(range(10))
>>> print(rangelist)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

for number in range(10):
# Check if number is one of
# the numbers in the tuple.
if number in (3, 4, 7, 9):
# "Break" terminates a for without
# executing the "else" clause.
break
else:
# "Continue" starts the next iteration
# of the loop. It's rather useless here,
# as it's the last statement of the loop.
continue
else:
# The "else" clause is optional and is
# executed only if the loop didn't "break".
pass # Do nothing

if rangelist[1] == 2:
print("The second item (lists are 0-based) is 2")
elif rangelist[1] == 3:
print("The second item (lists are 0-based) is 3")
else:
print("Dunno")

while rangelist[1] == 1:
print("We are trapped in an infinite loop!")